4k^2+10k+6=0

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Solution for 4k^2+10k+6=0 equation: 



4k^2+10k+6=0

a = 4; b = 10; c = +6;
Δ = b2-4ac
Δ = 102-4·4·6
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2}{2*4}=\frac{-12}{8}
=-1+1/2
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2}{2*4}=\frac{-8}{8}
=-1
$

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